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算法与数据结构 · LeetCode 22

LeetCode 22. 括号生成

给定 n 对括号,生成所有合法的括号组合。合法的意思是:每个右括号都能和前面某个未配对的左括号匹配。暴力做法是枚举全部 2^(2n) 个由 ( 和 ) 组成的串,再逐个检查;更好的做法是回溯,在生成的过程中只走合法的分支:左括号还没用满 n 个就可以放,右括号只有在"已放的左括号比右括号多"时才可以放。本文用真实运行的数据展示合法串的个数(卡特兰数)、剪枝带来的实际加速,给出五种语言的实现,并把回溯过程做成分步演示。

200
组随机对拍,与暴力解的结果全部一致
32 步
分步演示,每一帧都来自解法的真实执行,另附 5 种语言实现

题意与示例

完整题目见官方页面(链接在文末)。结果的顺序不作要求,核对时按集合比较。基准解枚举全部 2^(2n) 个串并逐个检查,与回溯是两种独立的写法。一共 8 组用例,n 从 1 到 8:

真实实测 · 本机执行输出
输入 [1]
输出 ["()"]
输入 [2]
输出 ["(())","()()"]
输入 [3]
输出 ["((()))","(()())","(())()","()(())","()()()"]
输入 [4]
输出 ["(((())))","((()()))","((())())","((()))()","(()(()))","(()()())","(()())()","(())(())","(())()()","()((()))","()(()())","()(())()","()()(())","()()()()"]
输入 [5]
输出 ["((((()))))","(((()())))","(((())()))","(((()))())","(((())))()","((()(())))","((()()()))","((()())())","((()()))()","((())(()))","((())()())","((())())()","((()))(())","((()))()()","(()((())))","(()(()()))","(()(())())","(()(()))()","(()()(()))","(()()()())","(()()())()","(()())(())","(()())()()","(())((()))","(())(()())","(())(())()","(())()(())","(())()()()","()(((())))","()((()()))","()((())())","()((()))()","()(()(()))","()(()()())","()(()())()","()(())(())","()(())()()","()()((()))","()()(()())","()()(())()","()()()(())","()()()()()"]
输入 [6]
输出 ["(((((())))))","((((()()))))","((((())())))","((((()))()))","((((())))())","((((()))))()","(((()(()))))","(((()()())))","(((()())()))","(((()()))())","(((()())))()","(((())(())))","(((())()()))","(((())())())","(((())()))()","(((()))(()))","(((()))()())","(((()))())()","(((())))(())","(((())))()()","((()((()))))","((()(()())))","((()(())()))","((()(()))())","((()(())))()","((()()(())))","((()()()()))","((()()())())","((()()()))()","((()())(()))","((()())()())","((()())())()","((()()))(())","((()()))()()","((())((())))","((())(()()))","((())(())())","((())(()))()","((())()(()))","((())()()())","((())()())()","((())())(())","((())())()()","((()))((()))","((()))(()())","((()))(())()","((()))()(())","((()))()()()","(()(((()))))","(()((()())))","(()((())()))","(()((()))())","(()((())))()","(()(()(())))","(()(()()()))","(()(()())())","(()(()()))()","(()(())(()))","(()(())()())","(()(())())()","(()(()))(())","(()(()))()()","(()()((())))","(()()(()()))","(()()(())())","(()()(()))()","(()()()(()))","(()()()()())","(()()()())()","(()()())(())","(()()())()()","(()())((()))","(()())(()())","(()())(())()","(()())()(())","(()())()()()","(())(((())))","(())((()()))","(())((())())","(())((()))()","(())(()(()))","(())(()()())","(())(()())()","(())(())(())","(())(())()()","(())()((()))","(())()(()())","(())()(())()","(())()()(())","(())()()()()","()((((()))))","()(((()())))","()(((())()))","()(((()))())","()(((())))()","()((()(())))","()((()()()))","()((()())())","()((()()))()","()((())(()))","()((())()())","()((())())()","()((()))(())","()((()))()()","()(()((())))","()(()(()()))","()(()(())())","()(()(()))()","()(()()(()))","()(()()()())","()(()()())()","()(()())(())","()(()())()()","()(())((()))","()(())(()())","()(())(())()","()(())()(())","()(())()()()","()()(((())))","()()((()()))","()()((())())","()()((()))()","()()(()(()))","()()(()()())","()()(()())()","()()(())(())","()()(())()()","()()()((()))","()()()(()())","()()()(())()","()()()()(())","()()()()()()"]

合法括号串有多少个?

我让回溯真实地生成了 n 从 1 到 10 的全部结果,并与卡特兰数公式 C(2n, n) / (n + 1) 对照,同时列出全部 2^(2n) 个串的数量,看看合法的占多少:

真实实测 · 本机执行输出
n | 结果个数 | 卡特兰数 C(2n,n)/(n+1) | 全部 2^(2n) 个串 | 合法占比
 1 |        1 |                      1 |                4 | 25.0000%
 2 |        2 |                      2 |               16 | 12.5000%
 3 |        5 |                      5 |               64 | 7.8125%
 4 |       14 |                     14 |              256 | 5.4688%
 5 |       42 |                     42 |             1024 | 4.1016%
 6 |      132 |                    132 |             4096 | 3.2227%
 7 |      429 |                    429 |            16384 | 2.6184%
 8 |     1430 |                   1430 |            65536 | 2.1820%
 9 |     4862 |                   4862 |           262144 | 1.8547%
10 |    16796 |                  16796 |          1048576 | 1.6018%

每一行的结果个数都和卡特兰数公式完全相同(n = 10 时是 16796)。n = 10 时全部 1048576 个串里只有约 1.6% 是合法的,也就是说暴力枚举会检查大量注定无效的串,这是回溯剪枝的价值所在。

剪枝到底省了多少

"不剪枝"的版本同样用回溯,但每个位置都可以放两种括号,放满 2n 个之后再检查是否合法。它与本文的解法结果完全一致,只是慢得多。下面是真实耗时,每个规模取三次中最快的一次:

真实实测 · 本机执行输出
n | 剪枝回溯耗时 | 不剪枝(放满再检查)耗时 | 结果一致
 6 |       0.15 ms |               1.33 ms | True
 8 |       0.77 ms |              26.87 ms | True
10 |      10.07 ms |             349.53 ms | True

n = 10 时,剪枝版本是 7.74ms,不剪枝版本是 325.72ms,约 42 倍。剪枝把搜索限制在合法的前缀上,搜索的规模与结果个数同一量级,而不是 4 的 n 次方。

回溯:五种语言的实现

dfs(open, close) 记录已经放了几个左括号和几个右括号。路径长度达到 2n 时收集结果;否则如果左括号没用满就放左括号并递归,再撤销;如果右括号比左括号少就放右括号并递归,再撤销。Python、Java、Go、JavaScript、C++ 都是真实编译运行的。

Python · 解法代码def solve(n): res = [] path = [] def dfs(open_, close): if len(path) == 2 * n: res.append("".join(path)) return if open_ < n: # 左括号还没用完,可以放 path.append("(") dfs(open_ + 1, close) path.pop() if close < open_: # 右括号只能在"有未配对的左括号"时放 path.append(")") dfs(open_, close + 1) path.pop() dfs(0, 0) return res
真实实测 · Python · 前几组用例的输出
$ python3 solution.py   # 统一入口:逐行读取 cases.jsonl,调用上面的 solve,打印 JSON
[1]  →  ["()"]
[2]  →  ["(())","()()"]
[3]  →  ["((()))","(()())","(())()","()(())","()()()"]
[4]  →  ["(((())))","((()()))","((())())","((()))()","(()(()))","(()()())","(()())()","(())(())","(())()()","()((()))","()(()())","()(())()","()()(())","()()()()"]
[5]  →  ["((((()))))","(((()())))","(((())()))","(((()))())","(((())))()","((()(())))","((()()()))","((()())())","((()()))()","((())(()))","((())()())","((())())()","((()))(())","((()))()()","(()((())))","(()(()()))","(()(())())","(()(()))()","(()()(()))","(()()()())","(()()())()","(()())(())","(()())()()","(())((()))","(())(()())","(())(())()","(())()(())","(())()()()","()(((())))","()((()()))","()((())())","()((()))()","()(()(()))","()(()()())","()(()())()","()(())(())","()(())()()","()()((()))","()()(()())","()()(())()","()()()(())","()()()()()"]
[6]  →  ["(((((())))))","((((()()))))","((((())())))","((((()))()))","((((())))())","((((()))))()","(((()(()))))","(((()()())))","(((()())()))","(((()()))())","(((()())))()","(((())(())))","(((())()()))","(((())())())","(((())()))()","(((()))(()))","(((()))()())","(((()))())()","(((())))(())","(((())))()()","((()((()))))","((()(()())))","((()(())()))","((()(()))())","((()(())))()","((()()(())))","((()()()()))","((()()())())","((()()()))()","((()())(()))","((()())()())","((()())())()","((()()))(())","((()()))()()","((())((())))","((())(()()))","((())(())())","((())(()))()","((())()(()))","((())()()())","((())()())()","((())())(())","((())())()()","((()))((()))","((()))(()())","((()))(())()","((()))()(())","((()))()()()","(()(((()))))","(()((()())))","(()((())()))","(()((()))())","(()((())))()","(()(()(())))","(()(()()()))","(()(()())())","(()(()()))()","(()(())(()))","(()(())()())","(()(())())()","(()(()))(())","(()(()))()()","(()()((())))","(()()(()()))","(()()(())())","(()()(()))()","(()()()(()))","(()()()()())","(()()()())()","(()()())(())","(()()())()()","(()())((()))","(()())(()())","(()())(())()","(()())()(())","(()())()()()","(())(((())))","(())((()()))","(())((())())","(())((()))()","(())(()(()))","(())(()()())","(())(()())()","(())(())(())","(())(())()()","(())()((()))","(())()(()())","(())()(())()","(())()()(())","(())()()()()","()((((()))))","()(((()())))","()(((())()))","()(((()))())","()(((())))()","()((()(())))","()((()()()))","()((()())())","()((()()))()","()((())(()))","()((())()())","()((())())()","()((()))(())","()((()))()()","()(()((())))","()(()(()()))","()(()(())())","()(()(()))()","()(()()(()))","()(()()()())","()(()()())()","()(()())(())","()(()())()()","()(())((()))","()(())(()())","()(())(())()","()(())()(())","()(())()()()","()()(((())))","()()((()()))","()()((())())","()()((()))()","()()(()(()))","()()(()()())","()()(()())()","()()(())(())","()()(())()()","()()()((()))","()()()(()())","()()()(())()","()()()()(())","()()()()()()"]
Java · 解法代码class Solution { public List<String> generateParenthesis(int n) { List<String> res = new ArrayList<>(); dfs(n, 0, 0, new StringBuilder(), res); return res; } private void dfs(int n, int open, int close, StringBuilder path, List<String> res) { if (path.length() == 2 * n) { res.add(path.toString()); return; } if (open < n) { // 左括号还没用完,可以放 path.append('('); dfs(n, open + 1, close, path, res); path.deleteCharAt(path.length() - 1); } if (close < open) { // 右括号只能在"有未配对的左括号"时放 path.append(')'); dfs(n, open, close + 1, path, res); path.deleteCharAt(path.length() - 1); } } }
真实实测 · Java · 前几组用例的输出
$ javac -d build Main.java Solution.java && java -cp build Main < cases.jsonl
[1]  →  ["()"]
[2]  →  ["(())","()()"]
[3]  →  ["((()))","(()())","(())()","()(())","()()()"]
[4]  →  ["(((())))","((()()))","((())())","((()))()","(()(()))","(()()())","(()())()","(())(())","(())()()","()((()))","()(()())","()(())()","()()(())","()()()()"]
[5]  →  ["((((()))))","(((()())))","(((())()))","(((()))())","(((())))()","((()(())))","((()()()))","((()())())","((()()))()","((())(()))","((())()())","((())())()","((()))(())","((()))()()","(()((())))","(()(()()))","(()(())())","(()(()))()","(()()(()))","(()()()())","(()()())()","(()())(())","(()())()()","(())((()))","(())(()())","(())(())()","(())()(())","(())()()()","()(((())))","()((()()))","()((())())","()((()))()","()(()(()))","()(()()())","()(()())()","()(())(())","()(())()()","()()((()))","()()(()())","()()(())()","()()()(())","()()()()()"]
[6]  →  ["(((((())))))","((((()()))))","((((())())))","((((()))()))","((((())))())","((((()))))()","(((()(()))))","(((()()())))","(((()())()))","(((()()))())","(((()())))()","(((())(())))","(((())()()))","(((())())())","(((())()))()","(((()))(()))","(((()))()())","(((()))())()","(((())))(())","(((())))()()","((()((()))))","((()(()())))","((()(())()))","((()(()))())","((()(())))()","((()()(())))","((()()()()))","((()()())())","((()()()))()","((()())(()))","((()())()())","((()())())()","((()()))(())","((()()))()()","((())((())))","((())(()()))","((())(())())","((())(()))()","((())()(()))","((())()()())","((())()())()","((())())(())","((())())()()","((()))((()))","((()))(()())","((()))(())()","((()))()(())","((()))()()()","(()(((()))))","(()((()())))","(()((())()))","(()((()))())","(()((())))()","(()(()(())))","(()(()()()))","(()(()())())","(()(()()))()","(()(())(()))","(()(())()())","(()(())())()","(()(()))(())","(()(()))()()","(()()((())))","(()()(()()))","(()()(())())","(()()(()))()","(()()()(()))","(()()()()())","(()()()())()","(()()())(())","(()()())()()","(()())((()))","(()())(()())","(()())(())()","(()())()(())","(()())()()()","(())(((())))","(())((()()))","(())((())())","(())((()))()","(())(()(()))","(())(()()())","(())(()())()","(())(())(())","(())(())()()","(())()((()))","(())()(()())","(())()(())()","(())()()(())","(())()()()()","()((((()))))","()(((()())))","()(((())()))","()(((()))())","()(((())))()","()((()(())))","()((()()()))","()((()())())","()((()()))()","()((())(()))","()((())()())","()((())())()","()((()))(())","()((()))()()","()(()((())))","()(()(()()))","()(()(())())","()(()(()))()","()(()()(()))","()(()()()())","()(()()())()","()(()())(())","()(()())()()","()(())((()))","()(())(()())","()(())(())()","()(())()(())","()(())()()()","()()(((())))","()()((()()))","()()((())())","()()((()))()","()()(()(()))","()()(()()())","()()(()())()","()()(())(())","()()(())()()","()()()((()))","()()()(()())","()()()(())()","()()()()(())","()()()()()()"]
Go · 解法代码func generateParenthesis(n int) []string { res := []string{} path := make([]byte, 0, 2*n) var dfs func(open, close int) dfs = func(open, close int) { if len(path) == 2*n { res = append(res, string(path)) return } if open < n { // 左括号还没用完,可以放 path = append(path, '(') dfs(open+1, close) path = path[:len(path)-1] } if close < open { // 右括号只能在"有未配对的左括号"时放 path = append(path, ')') dfs(open, close+1) path = path[:len(path)-1] } } dfs(0, 0) return res }
真实实测 · Go · 前几组用例的输出
$ go build -o bin . && ./bin < cases.jsonl
[1]  →  ["()"]
[2]  →  ["(())","()()"]
[3]  →  ["((()))","(()())","(())()","()(())","()()()"]
[4]  →  ["(((())))","((()()))","((())())","((()))()","(()(()))","(()()())","(()())()","(())(())","(())()()","()((()))","()(()())","()(())()","()()(())","()()()()"]
[5]  →  ["((((()))))","(((()())))","(((())()))","(((()))())","(((())))()","((()(())))","((()()()))","((()())())","((()()))()","((())(()))","((())()())","((())())()","((()))(())","((()))()()","(()((())))","(()(()()))","(()(())())","(()(()))()","(()()(()))","(()()()())","(()()())()","(()())(())","(()())()()","(())((()))","(())(()())","(())(())()","(())()(())","(())()()()","()(((())))","()((()()))","()((())())","()((()))()","()(()(()))","()(()()())","()(()())()","()(())(())","()(())()()","()()((()))","()()(()())","()()(())()","()()()(())","()()()()()"]
[6]  →  ["(((((())))))","((((()()))))","((((())())))","((((()))()))","((((())))())","((((()))))()","(((()(()))))","(((()()())))","(((()())()))","(((()()))())","(((()())))()","(((())(())))","(((())()()))","(((())())())","(((())()))()","(((()))(()))","(((()))()())","(((()))())()","(((())))(())","(((())))()()","((()((()))))","((()(()())))","((()(())()))","((()(()))())","((()(())))()","((()()(())))","((()()()()))","((()()())())","((()()()))()","((()())(()))","((()())()())","((()())())()","((()()))(())","((()()))()()","((())((())))","((())(()()))","((())(())())","((())(()))()","((())()(()))","((())()()())","((())()())()","((())())(())","((())())()()","((()))((()))","((()))(()())","((()))(())()","((()))()(())","((()))()()()","(()(((()))))","(()((()())))","(()((())()))","(()((()))())","(()((())))()","(()(()(())))","(()(()()()))","(()(()())())","(()(()()))()","(()(())(()))","(()(())()())","(()(())())()","(()(()))(())","(()(()))()()","(()()((())))","(()()(()()))","(()()(())())","(()()(()))()","(()()()(()))","(()()()()())","(()()()())()","(()()())(())","(()()())()()","(()())((()))","(()())(()())","(()())(())()","(()())()(())","(()())()()()","(())(((())))","(())((()()))","(())((())())","(())((()))()","(())(()(()))","(())(()()())","(())(()())()","(())(())(())","(())(())()()","(())()((()))","(())()(()())","(())()(())()","(())()()(())","(())()()()()","()((((()))))","()(((()())))","()(((())()))","()(((()))())","()(((())))()","()((()(())))","()((()()()))","()((()())())","()((()()))()","()((())(()))","()((())()())","()((())())()","()((()))(())","()((()))()()","()(()((())))","()(()(()()))","()(()(())())","()(()(()))()","()(()()(()))","()(()()()())","()(()()())()","()(()())(())","()(()())()()","()(())((()))","()(())(()())","()(())(())()","()(())()(())","()(())()()()","()()(((())))","()()((()()))","()()((())())","()()((()))()","()()(()(()))","()()(()()())","()()(()())()","()()(())(())","()()(())()()","()()()((()))","()()()(()())","()()()(())()","()()()()(())","()()()()()()"]
JavaScript · 解法代码function generateParenthesis(n) { const res = []; const path = []; const dfs = (open, close) => { if (path.length === 2 * n) { res.push(path.join("")); return; } if (open < n) { // 左括号还没用完,可以放 path.push("("); dfs(open + 1, close); path.pop(); } if (close < open) { // 右括号只能在"有未配对的左括号"时放 path.push(")"); dfs(open, close + 1); path.pop(); } }; dfs(0, 0); return res; }
真实实测 · JavaScript · 前几组用例的输出
$ node run.js < cases.jsonl
[1]  →  ["()"]
[2]  →  ["(())","()()"]
[3]  →  ["((()))","(()())","(())()","()(())","()()()"]
[4]  →  ["(((())))","((()()))","((())())","((()))()","(()(()))","(()()())","(()())()","(())(())","(())()()","()((()))","()(()())","()(())()","()()(())","()()()()"]
[5]  →  ["((((()))))","(((()())))","(((())()))","(((()))())","(((())))()","((()(())))","((()()()))","((()())())","((()()))()","((())(()))","((())()())","((())())()","((()))(())","((()))()()","(()((())))","(()(()()))","(()(())())","(()(()))()","(()()(()))","(()()()())","(()()())()","(()())(())","(()())()()","(())((()))","(())(()())","(())(())()","(())()(())","(())()()()","()(((())))","()((()()))","()((())())","()((()))()","()(()(()))","()(()()())","()(()())()","()(())(())","()(())()()","()()((()))","()()(()())","()()(())()","()()()(())","()()()()()"]
[6]  →  ["(((((())))))","((((()()))))","((((())())))","((((()))()))","((((())))())","((((()))))()","(((()(()))))","(((()()())))","(((()())()))","(((()()))())","(((()())))()","(((())(())))","(((())()()))","(((())())())","(((())()))()","(((()))(()))","(((()))()())","(((()))())()","(((())))(())","(((())))()()","((()((()))))","((()(()())))","((()(())()))","((()(()))())","((()(())))()","((()()(())))","((()()()()))","((()()())())","((()()()))()","((()())(()))","((()())()())","((()())())()","((()()))(())","((()()))()()","((())((())))","((())(()()))","((())(())())","((())(()))()","((())()(()))","((())()()())","((())()())()","((())())(())","((())())()()","((()))((()))","((()))(()())","((()))(())()","((()))()(())","((()))()()()","(()(((()))))","(()((()())))","(()((())()))","(()((()))())","(()((())))()","(()(()(())))","(()(()()()))","(()(()())())","(()(()()))()","(()(())(()))","(()(())()())","(()(())())()","(()(()))(())","(()(()))()()","(()()((())))","(()()(()()))","(()()(())())","(()()(()))()","(()()()(()))","(()()()()())","(()()()())()","(()()())(())","(()()())()()","(()())((()))","(()())(()())","(()())(())()","(()())()(())","(()())()()()","(())(((())))","(())((()()))","(())((())())","(())((()))()","(())(()(()))","(())(()()())","(())(()())()","(())(())(())","(())(())()()","(())()((()))","(())()(()())","(())()(())()","(())()()(())","(())()()()()","()((((()))))","()(((()())))","()(((())()))","()(((()))())","()(((())))()","()((()(())))","()((()()()))","()((()())())","()((()()))()","()((())(()))","()((())()())","()((())())()","()((()))(())","()((()))()()","()(()((())))","()(()(()()))","()(()(())())","()(()(()))()","()(()()(()))","()(()()()())","()(()()())()","()(()())(())","()(()())()()","()(())((()))","()(())(()())","()(())(())()","()(())()(())","()(())()()()","()()(((())))","()()((()()))","()()((())())","()()((()))()","()()(()(()))","()()(()()())","()()(()())()","()()(())(())","()()(())()()","()()()((()))","()()()(()())","()()()(())()","()()()()(())","()()()()()()"]
C++ · 解法代码#include <string> #include <vector> using namespace std; class Solution { void dfs(int n, int open, int close, string& path, vector<string>& res) { if ((int)path.size() == 2 * n) { res.push_back(path); return; } if (open < n) { // 左括号还没用完,可以放 path.push_back('('); dfs(n, open + 1, close, path, res); path.pop_back(); } if (close < open) { // 右括号只能在"有未配对的左括号"时放 path.push_back(')'); dfs(n, open, close + 1, path, res); path.pop_back(); } } public: vector<string> generateParenthesis(int n) { vector<string> res; string path; dfs(n, 0, 0, path, res); return res; } };
真实实测 · C++ · 前几组用例的输出
$ clang++ -std=c++17 -O2 -o bin sol.cpp && ./bin < cases.jsonl
[1]  →  ["()"]
[2]  →  ["(())","()()"]
[3]  →  ["((()))","(()())","(())()","()(())","()()()"]
[4]  →  ["(((())))","((()()))","((())())","((()))()","(()(()))","(()()())","(()())()","(())(())","(())()()","()((()))","()(()())","()(())()","()()(())","()()()()"]
[5]  →  ["((((()))))","(((()())))","(((())()))","(((()))())","(((())))()","((()(())))","((()()()))","((()())())","((()()))()","((())(()))","((())()())","((())())()","((()))(())","((()))()()","(()((())))","(()(()()))","(()(())())","(()(()))()","(()()(()))","(()()()())","(()()())()","(()())(())","(()())()()","(())((()))","(())(()())","(())(())()","(())()(())","(())()()()","()(((())))","()((()()))","()((())())","()((()))()","()(()(()))","()(()()())","()(()())()","()(())(())","()(())()()","()()((()))","()()(()())","()()(())()","()()()(())","()()()()()"]
[6]  →  ["(((((())))))","((((()()))))","((((())())))","((((()))()))","((((())))())","((((()))))()","(((()(()))))","(((()()())))","(((()())()))","(((()()))())","(((()())))()","(((())(())))","(((())()()))","(((())())())","(((())()))()","(((()))(()))","(((()))()())","(((()))())()","(((())))(())","(((())))()()","((()((()))))","((()(()())))","((()(())()))","((()(()))())","((()(())))()","((()()(())))","((()()()()))","((()()())())","((()()()))()","((()())(()))","((()())()())","((()())())()","((()()))(())","((()()))()()","((())((())))","((())(()()))","((())(())())","((())(()))()","((())()(()))","((())()()())","((())()())()","((())())(())","((())())()()","((()))((()))","((()))(()())","((()))(())()","((()))()(())","((()))()()()","(()(((()))))","(()((()())))","(()((())()))","(()((()))())","(()((())))()","(()(()(())))","(()(()()()))","(()(()())())","(()(()()))()","(()(())(()))","(()(())()())","(()(())())()","(()(()))(())","(()(()))()()","(()()((())))","(()()(()()))","(()()(())())","(()()(()))()","(()()()(()))","(()()()()())","(()()()())()","(()()())(())","(()()())()()","(()())((()))","(()())(()())","(()())(())()","(()())()(())","(()())()()()","(())(((())))","(())((()()))","(())((())())","(())((()))()","(())(()(()))","(())(()()())","(())(()())()","(())(())(())","(())(())()()","(())()((()))","(())()(()())","(())()(())()","(())()()(())","(())()()()()","()((((()))))","()(((()())))","()(((())()))","()(((()))())","()(((())))()","()((()(())))","()((()()()))","()((()())())","()((()()))()","()((())(()))","()((())()())","()((())())()","()((()))(())","()((()))()()","()(()((())))","()(()(()()))","()(()(())())","()(()(()))()","()(()()(()))","()(()()()())","()(()()())()","()(()())(())","()(()())()()","()(())((()))","()(())(()())","()(())(())()","()(())()(())","()(())()()()","()()(((())))","()()((()()))","()()((())())","()()((()))()","()()(()(()))","()()(()()())","()()(()())()","()()(())(())","()()(())()()","()()()((()))","()()()(()())","()()()(())()","()()()()(())","()()()()()()"]
真实实测 · 本机执行输出
共 8 组用例(含边界),以暴力解的结果为基准逐组比对:
  Python      通过 8/8
  Java        通过 8/8
  Go          通过 8/8
  JavaScript  通过 8/8
  C++         通过 8/8

复杂度实测

下面是括号对数 n 为 4、6、8、10 时,全部枚举再检查的暴力解与回溯的耗时:

真实实测 · 本机执行输出
n(括号对数) | 暴力解 | 本文解法
         4 |     0.037 ms | 0.006 ms
         6 |     0.643 ms | 0.057 ms
         8 |    13.716 ms | 0.670 ms
        10 |      (未测,太慢) | 9.426 ms

n 每增加 2,暴力解的耗时增长约 15 到 19 倍(4 的平方是 16),回溯每增加 2 增长约 8 到 16 倍(n = 4 到 6 是 8.6 倍,6 到 8 是 15.9 倍,8 到 10 是 8.4 倍),与结果个数每增加两对增长 9 到 12 倍的量级相当(例如 n = 6 到 8 是 132 到 1430);中间那一档偏高,我没有细究,小规模下计时的噪声也比较大。n = 10 时暴力解没有再测。

随机对拍

Python 版本另外和暴力解做了随机对拍:

真实实测 · 本机执行输出
随机对拍 200 组(n 取 1 到 7 的随机值(结果按集合比较,不要求顺序)),solve 与 brute 的结果全部一致。

n 只有 1 到 8 这几种取值,所以固定用例已经覆盖了全部小规模输入;随机对拍主要用来确认没有遗漏。另外四种语言只在上面 8 组固定用例上验证过。

分步演示:回溯和剪枝

下面的演示用 n = 3,共 5 个结果。每一帧都是把上面的解法在这组输入上真实执行记录下来的,运行器还检查了演示收集到的结果与 solve 一致。注意"右括号已经和左括号一样多,不能再放 )"的帧:这就是剪枝,直接不生成非法前缀。

括号生成:n = 3

    参考与说明

    • 官方题目页:LeetCode 22. 括号生成。本文只用自己的话概括了题意,完整约束以官方页面为准。
    • 数据来自本机真实运行,五种语言的版本写在页脚;耗时对比只用 Python 测量。
    • 没有覆盖:按长度做动态规划(用更小的括号对拼出更大的)的做法;结果个数的数学证明,本文只验证了 n 从 1 到 10 与卡特兰数一致。
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